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Home/ Questions/Q 618557
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:33:32+00:00 2026-05-13T18:33:32+00:00

For the record, I’m NOT a Java Beginner, but — rather – an intermediate-level

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For the record, I’m NOT a Java Beginner, but — rather – an intermediate-level guy who kinda forgot a bit about fundamentals about Java.

class C{
    public static void main(String a[]){
        C c1=new C();
        C c2=m1(c1);        //line 4
        C c3=new C();
        c2=c3;              // line 6
        anothermethod();
    }
    static C m1(C ob1){
        ob1 =new C();      // line 10
        return ob1;
    }
    void anothermethod(){}
}

From the above code:

  • Why is it that after line 6, 2 objects of type C are eligible for Garbage Collection(GC)?

  • Why isn’t it that in line 4 and line 10, a copy of c1 is passed into the m1() method. So, eventually in line 6, there is going to be 1 Object (not 2) that are going to be eligible for GC. After all, isn’t java pass -by-value rather than pass-by-reference?

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  1. Editorial Team
    Editorial Team
    2026-05-13T18:33:33+00:00Added an answer on May 13, 2026 at 6:33 pm

    What makes you think two objects of type C are available for GC after line 6? I only see one (c2). What tool are you using that tells you otherwise?

    Regarding your question about passing c1 into your m1 method: What you pass (by value) is a reference to the object — a handle by which you can grab the object, if you will — not a copy of it. The fact you pass a reference into m1 is completely irrelevant, in fact — you never use that reference, you immediately overwrite it with a reference to a new object, which you then return (this does not affect the c1 that is still referenced in main).

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