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Home/ Questions/Q 6599765
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T18:32:00+00:00 2026-05-25T18:32:00+00:00

For this code I created that outputs the ASCII characters corresponding to int s,

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For this code I created that outputs the ASCII characters corresponding to ints, I need to print out 16 ASCIIs per line. How would I go about doing so? I’m not sure how to approach these? Do I create another for loop inside?

int main()
{
    int x = 0;

    for (int i = 0; i <= 127; i++)
    {
        int x = i;
        char y = (char) x;
        cout << y;
    }

    return 0;
}

Or should I put the cout outside with 16 separate lines? I am trying to print 17 ASCIIs starting from 1 in a row.

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  1. Editorial Team
    Editorial Team
    2026-05-25T18:32:01+00:00Added an answer on May 25, 2026 at 6:32 pm

    Use another variable that counts up along with i. When it reaches 16, reset it and print a new line. Repeat until the loop terminates.

    i.e.(I may be off by one here, I didn’t think about it too deeply)

    for (int i=0, j=1; i<=127; i++,j++)
    {
        int x = i;
        char y = (char) x;
        cout << y;
    
        if (j == 16) {
            j = 0;
            cout << '\n';
        }
    }
    

    Alternatively, you could just check if (i % 16 == 0)

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