Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6622961
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T21:28:27+00:00 2026-05-25T21:28:27+00:00

For this question, consider the following sample: @Entity public class File { public static

  • 0

For this question, consider the following sample:

@Entity
public class File {
    public static enum Permission { READABLE, WRITEABLE, EXECUTABLE }

    @ElementCollection
    @Enumerated(EnumType.ORDINAL)
    Set<Permission> permissions;

    // Omitted
}

Assuming that the enum values are stored in the ordinal form, does JPA always create an extra table for this set? Can I alter this in order to make this not to be an one-to-many relationship, i.e., using a column instead of an extra table?

Thanks.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T21:28:27+00:00Added an answer on May 25, 2026 at 9:28 pm
    1. “one-to-many” is a type of entity association. This is a collection of values, so it can’t be a one-to-many.
    2. It’s physically impossible to store multiple values in a single field in a single row, so no, you can’t make it do that.
    3. Essentially what you’re asking for is a basic property, like private String permissions;. That would use a single column in the same table.
    4. If you’re wanting to pack multiple values into a single value, like manually combining all the permissions into a comma-delimited string when Hibernate saves it, you’ll want to write a custom UserType to do that.
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Consider the following sample code: #include <iostream> using namespace std; class base { public:
This might be a entity framework related question, anyway, here goes: Consider the following
Consider the following sample code: class Base { public: void f(); virtual void vf();
This is a very basic question, so please bear with me. Consider the following
Consider the following class: class MyClass { public: template<class T> typename T::result_type apply(T& func)
Consider the following code sample: private void AddEnvelope(MailMessage mail) { if (this.CopyEnvelope) { //
This is mostly an out-of-curiosity question. Consider the following functions var closure ; function
Consider the following sample code below: #include <iostream> using namespace std; class base {
Consider the following class: class Something : ISomething { public void DoesSomething(int x) {
I got the following code that generate a DLL (sample exemple) : public class

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.