Question

for *** :
   try:
       xx = A(
          a=x,
          b=y
       )
       xx.save()
   except:
     pass

here is my question: once one of the “xx” saved error, others will not save success.
Does any one know why? thanks!

here is the error message

Exception
[2011-08-22 14:02:23,879: WARNING/PoolWorker-1] RuntimeError
[2011-08-22 14:02:23,879: WARNING/PoolWorker-1] :
[2011-08-22 14:02:23,879: WARNING/PoolWorker-1] 'generator ignored GeneratorExit'
[2011-08-22 14:02:23,879: WARNING/PoolWorker-1] in
[2011-08-22 14:02:23,880: WARNING/PoolWorker-1] <generator object msg_iter_page at 0x2ec28c0>
[2011-08-22 14:02:23,880: WARNING/PoolWorker-1] ignored

Answer 1

You catch every exception with this statement:

except:
   pass

GeneratorExit is just an exception. This should not be caught. Please catch only the exceptions, you expect.