Question

Forgive me if this question has already been asked, but… I’m trying to select data from 2 different tables in a database and count all the data in one table that is equal to the data in the second table if that makes sense? Below is the code I am trying to use

$select = "SELECT * FROM client_id, clientid, COUNT(client_id) FROM enquiry, check_s WHERE client_id = clientid";

Answer 1

Your query appears to be syntactically wrong.
What you can try is to join the two tables on a primary key(id?) and any other fields you’re trying to match. The basic syntax would be like this:

SELECT * FROM 
DB1.Table1 
JOIN DB2.Table2 
ON DB1.Table1.PrimaryKey = DB2.Table2.PrimaryKey;

If you’re looking for an exact data match, you may have to join the tables based on all fields(in the ON clause in the above query).

Edit:

Now that you’ve explained it, you can try this:

SELECT table1.*, count(*) as `n` FROM table1
JOIN table2 
ON table1.field = table2.field;

Again, if you need to compare more fields, just include them in the ON clause, and set conditions in the WHERE clause.