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Home/ Questions/Q 959197
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T00:59:11+00:00 2026-05-16T00:59:11+00:00

friends, i am trying to upload file to php server using following tutorial http://getablogger.blogspot.com/2008/01/android-how-to-post-file-to-php-server.html

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friends,

i am trying to upload file to php server using following tutorial
http://getablogger.blogspot.com/2008/01/android-how-to-post-file-to-php-server.html

i dont know how to add parameters like

userid=”12312″;sessionid=”234″

in it.

any one guide me how to achieve this?

any help would be appreciated.

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  1. Editorial Team
    Editorial Team
    2026-05-16T00:59:11+00:00Added an answer on May 16, 2026 at 12:59 am

    How to make an http POST and adding parameters.

    how to add parameters? you must have something like.

    // Add your data  
    List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);  
    nameValuePairs.add(new BasicNameValuePair("userid", "12312"));  
    nameValuePairs.add(new BasicNameValuePair("sessionid", "234"));  
    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));  
    

    This is a complete method:

    public void postData() {
        // Create a new HttpClient and Post Header
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://www.yoursite.com/myexample.php");
    
    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);
        nameValuePairs.add(new BasicNameValuePair("id", "12345"));
        nameValuePairs.add(new BasicNameValuePair("stringdata", "stackoverflow.com is Cool!"));
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
    
        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(httppost);
        
       } catch (ClientProtocolException e) {
          // TODO Auto-generated catch block
       } catch (IOException e) {
          // TODO Auto-generated catch block
       }
    }
    
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