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Home/ Questions/Q 8496871
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T23:58:08+00:00 2026-06-10T23:58:08+00:00

Friends I have a big problem. I have several database connections. I have to

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Friends I have a big problem. I have several database connections. I have to use those connections dynamically in a mysql_query().
For example,

$db1=mysql_connect('port','username','password') or die("cannot connect to the database");
@mysql_select_db('db1') or die("Unable to select Database");

$db2=mysql_connect('port','username','password') or die("cannot connect to the database");
@mysql_select_db('db2') or die("Unable to select Database");

which connection to use is defined from a switch case.

switch(type){
case "1":
$link="$db1";
break;
case "2":
$link="$db2";
break;
}

my mysql_query is like this.

mysql_query("DELETE FROM table1 WHERE id='2'",$link);

unfortunately it’s not working
it says supplied argument is not a valid MySQL-Link resource

I have tried following also but no luck

mysql_query("DELETE FROM table1 WHERE id='2'".','.$link);

How can i do this? Any idea ??

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  1. Editorial Team
    Editorial Team
    2026-06-10T23:58:10+00:00Added an answer on June 10, 2026 at 11:58 pm

    Don’t transform the connection ids to strings in the switch statement by enclosing them with "! Just use the following:

    switch(type){
      case "1":
        $link=$db1;
        break;
      case "2":
        $link=$db2;
        break;
    }
    
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