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Home/ Questions/Q 6581679
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T16:11:02+00:00 2026-05-25T16:11:02+00:00

From an external file I generate the following dictionary: mydict = { ‘foo’ :

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From an external file I generate the following dictionary:

mydict = { 'foo' : 123, 'bar' : 456 }

Given a function that takes a **kwargs argument, how can generate the keyword-args from that dictionary?

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  1. Editorial Team
    Editorial Team
    2026-05-25T16:11:03+00:00Added an answer on May 25, 2026 at 4:11 pm
    def foo(**kwargs):
        pass
    
    foo(**{ 'foo' : 123, 'bar' : 456 })
    
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