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Home/ Questions/Q 550227
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T11:15:58+00:00 2026-05-13T11:15:58+00:00

from functools import wraps def a(): a=’aa’ def b(): b=bbb c=wraps(a)(b) print c#what happen?

  • 0
from functools import  wraps

def a():
    a='aa'
def b():
    b="bbb"

c=wraps(a)(b)
print c#what happen?

What is the wraps mean, example is the best.

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  1. Editorial Team
    Editorial Team
    2026-05-13T11:15:59+00:00Added an answer on May 13, 2026 at 11:15 am

    Quoted from the documentation:

    functools.wraps(wrapped[, assigned][, updated]) 
    

    This is a convenience function for invoking partial(update_wrapper, wrapped=wrapped, assigned=assigned, updated=updated) as a function decorator when defining a wrapper function. For example:

    >>> from functools import wraps
    >>> def my_decorator(f):
    ...     @wraps(f)
    ...     def wrapper(*args, **kwds):
    ...         print 'Calling decorated function'
    ...         return f(*args, **kwds)
    ...     return wrapper
    ...
    >>> @my_decorator
    ... def example():
    ...     """Docstring"""
    ...     print 'Called example function'
    ...
    >>> example()
    Calling decorated function
    Called example function
    >>> example.__name__
    'example'
    >>> example.__doc__
    'Docstring'
    

    Without the use of this decorator factory, the name of the example function would have been ‘wrapper’, and the docstring of the original example() would have been lost.

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