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Home/ Questions/Q 8540075
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T11:31:02+00:00 2026-06-11T11:31:02+00:00

From: http://docs.python.org/py3k/library/datetime.html#timedelta-objects A timedelta object represents a duration, the difference between two dates or

  • 0

From:

http://docs.python.org/py3k/library/datetime.html#timedelta-objects

A timedelta object represents a duration, the difference between two
dates or times.

So why i get error with this:

>>> from datetime import datetime, timedelta, time
>>> datetime.now() + timedelta(hours=12)
datetime.datetime(2012, 9, 17, 6, 24, 9, 635862)
>>> datetime.now().date() + timedelta(hours=12)
datetime.date(2012, 9, 16)

>>> datetime.now().time() + timedelta(hours=12)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for +: 'datetime.time' and 'datetime.timedelta'
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  1. Editorial Team
    Editorial Team
    2026-06-11T11:31:03+00:00Added an answer on June 11, 2026 at 11:31 am

    datetime.time objects do not support addition with datetime.timedeltas.

    There is one natural definition though, clock arithmetic.
    You could compute it like this:

    import datetime as dt
    now = dt.datetime.now()
    delta = dt.timedelta(hours = 12)
    t = now.time()
    print(t)
    # 12:39:11.039864
    
    print((dt.datetime.combine(dt.date(1,1,1),t) + delta).time())
    # 00:39:11.039864
    

    dt.datetime.combine(...) lifts the datetime.time t to a datetime.datetime object, the delta is then added, and the result is dropped back down to a datetime.time object.

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