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Home/ Questions/Q 1107119
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:53:36+00:00 2026-05-17T01:53:36+00:00

From jmorecfg.h : #define PACK_TWO_PIXELS(l,r) ((r<<16) | l) #define PACK_NEED_ALIGNMENT(ptr) (((int)(ptr))&3) #define WRITE_TWO_PIXELS(addr, pixels)

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From jmorecfg.h:

#define PACK_TWO_PIXELS(l,r)   ((r<<16) | l)
#define PACK_NEED_ALIGNMENT(ptr) (((int)(ptr))&3)
#define WRITE_TWO_PIXELS(addr, pixels) do {     \
         ((INT16*)(addr))[0] = (pixels);        \
         ((INT16*)(addr))[1] = (pixels)>>16;    \
    } while(0)
#define WRITE_TWO_ALIGNED_PIXELS(addr, pixels)  ((*(INT32*)(addr)) = pixels

Can someone explain the difference between WRITE_TWO_PIXELS and WRITE_TWO_ALIGNED_PIXELS? If pixels is a stack allocated uint32_t and addr & 3 == 0, shouldn’t they be equivalent?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:53:37+00:00Added an answer on May 17, 2026 at 1:53 am

    WRITE_TWO_PIXELS and WRITE_TWO_ALIGNED_PIXELS are equivalent for little endian machines but not for big endian architecture.

    [Example edited: thanks to Steve Jessop]

    Let, pixels = 0x0A0B0C0D

    For big endian machines, WRITE_TWO_PIXELS work as follows:

    ---------------------
    | 0B | 0A | 0D | 0C |
    ---------------------
      3    2    1    0          <--- addr
    

    where WRITE_TWO_ALIGNED_PIXELS will write as follows:

    ---------------------
    | 0D | 0C | 0B | 0A |
    ---------------------
      3    2    1    0          <--- addr
    
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