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Home/ Questions/Q 6756125
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:29:14+00:00 2026-05-26T13:29:14+00:00

From my experience with Windows 7 (64-bit) and Java, a 32-bit JRE uses less

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From my experience with Windows 7 (64-bit) and Java, a 32-bit JRE uses less memory and runs significantly faster than a 64-bit JRE (provided you don’t need or benefit from having a lot of memory). I imagine the same thing is true for Mac OSX (and other platforms) as well.

I am currently running OSX Lion (v10.7), and I have installed the standard Java app. Under Java Preferences, I see “Java SE 6” from “Apple Inc.” for both CPU-types “32-bit” and “64-bit” version “1.6.0_26-b03-383”. I have changed the preferred order to put the 32-bit version on top of the 64-bit version, hoping that this would make the 32-bit version default.

But “java -version” still says:

java version "1.6.0_26"
Java(TM) SE Runtime Environment (build 1.6.0_26-b03-383-11A511c)
Java HotSpot(TM) 64-Bit Server VM (build 20.1-b02-383, mixed mode)

Is it possible to use the 32-bit version by default? And how?

Also, does anyone have experiences / comparative measurements regarding speed and memory efficiency between the 32/64-bit versions?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:29:14+00:00Added an answer on May 26, 2026 at 1:29 pm

    I found out now, that the 32-bit JVM can be explicitly launched using the -d32 switch.

    On my machine, “java -version -d32” says:

    java version "1.6.0_26"
    Java(TM) SE Runtime Environment (build 1.6.0_26-b03-383-11A511c)
    Java HotSpot(TM) Client VM (build 20.1-b02-383, mixed mode)
    

    and although it doesn’t say so, it is a 32-bit JVM.

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