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Home/ Questions/Q 1105437
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:37:57+00:00 2026-05-17T01:37:57+00:00

From my lecture slides, it states: As illustrated in the code below an array

  • 0

From my lecture slides, it states:

As illustrated in the code below an array name can be assigned
to an appropriate pointer without the need for a preceding & operator.

int x;  
int a[3] = {0,1,2};  
int *pa = a;  
x = *pa;  
x = *(pa + 1);  
x = *(pa + 2);  
a += 2; /* invalid */  

Why is a += 2; invalid?

Can anyone help clarify?
Also feel free to edit the title if you think of a better one.

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:37:58+00:00Added an answer on May 17, 2026 at 1:37 am

    a += 2 gets translated to a = a + 2. Adding a number to an array is the same as adding a number to a pointer which is valid and yields a new pointer.

    The assignment is the problem – arrays are not lvalues, so you cannot assign anything to them. It is just not allowed. And even if you could there is a type mismatch here – you’re trying to assign a pointer to an array which does not make sense.

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