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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T21:47:05+00:00 2026-05-13T21:47:05+00:00

From perldoc -f each we read: There is a single iterator for each hash,

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From perldoc -f each we read:

There is a single iterator for each hash, shared by all each, keys, and values function calls in the program; it can be reset by reading all the elements from the hash, or by evaluating keys HASH or values HASH.

The iterator is not reset when you leave the scope containing the each(), and this can lead to bugs:

my %h = map { $_, 1 } qw(1 2 3);
while (my $k = each %h) { print "1: $k\n"; last }
while (my $k = each %h) { print "2: $k\n"       }

Output:

1: 1
2: 3
2: 2

What are the common workarounds for this behavior? And is it worth using each in general?

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  1. Editorial Team
    Editorial Team
    2026-05-13T21:47:05+00:00Added an answer on May 13, 2026 at 9:47 pm

    I think it is worth using as long as you are aware of this. It’s ideal when you need both key and value in iteration:

    while (my ($k,$v) = each %h) {
        say "$k = $v";
    }
    

    In your example you can reset the iterator by adding keys %h; like so:

    my %h = map { $_ => 1 } qw/1 2 3/;
    while (my $k = each %h) { print "1: $k\n"; last }
    keys %h;  # reset %h
    while (my $k = each %h) { print "2: $k\n" }
    

    From Perl 5.12 each will also allow iteration on an array.

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