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Home/ Questions/Q 8993003
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T23:05:44+00:00 2026-06-15T23:05:44+00:00

from PySide.QtCore import * from PySide.QtGui import * import sys import stackwid class Dialog(QDialog,stackwid.Ui_Dialog):

  • 0
from PySide.QtCore import *
from PySide.QtGui import *

import sys
import stackwid

class Dialog(QDialog,stackwid.Ui_Dialog):

    def __init__(self,parent = None):
        super(Dialog,self).__init__(parent)
        self.setupUi(self)


        self.camButton.clicked.connect(self.set())


    def set(self):

        self.stackedWidget.setCurrentIndex(1)


app = QApplication(sys.argv)
form = Dialog()
form.show()
app.exec_()

I wanted to connect clicked() signal emitted by camButton(PushButton) to slot which is a function set().This just does not run .

RuntimeError: Failed to connect signal clicked()
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  1. Editorial Team
    Editorial Team
    2026-06-15T23:05:45+00:00Added an answer on June 15, 2026 at 11:05 pm

    You don’t connect the signal to your set()-function, but to it’s return value. You just need to remove the parenthesis, then it should work:

    self.camButton.clicked.connect(self.set)
    
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