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Home/ Questions/Q 7070621
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T05:35:19+00:00 2026-05-28T05:35:19+00:00

From ?stringr::str_extract , I tried library(stringr) str_extract(number 123, \\d) # [1] 1 but I’d

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From ?stringr::str_extract, I tried

 library(stringr)
 str_extract("number 123", "\\d")
 # [1] "1"

but I’d like the full number 123. I couldn’t find the correct regular expression, or another function to perform this task. My workaround is a bit ugly,

as.numeric(str_split("number 123", " ")[[1]][2])
# [1] 123
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  1. Editorial Team
    Editorial Team
    2026-05-28T05:35:20+00:00Added an answer on May 28, 2026 at 5:35 am

    For this particular example, the following regular expression works:

    pat <- "(\\d)+"
    as.numeric(str_extract("number 123", pat))
    # [1] 123
    

    If you want to only pick out numbers that terminate the text string that they are in, add a $ to the end of the pattern above.

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