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Home/ Questions/Q 381265
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T15:04:07+00:00 2026-05-12T15:04:07+00:00

From what I understand, the backslash dot ( \. ) means one character of

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From what I understand, the backslash dot (\.) means one character of any character? So because backslash is an escape, it should be backslash backslash dot ("\\.")

What does this do to a string? I just saw this in an existing code I am working on. From what I understand, it will split the string into individual characters. Why do this instead of String.toCharArray(). So this splits the string to an array of string which contains only one char for each string in the array?

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  1. Editorial Team
    Editorial Team
    2026-05-12T15:04:08+00:00Added an answer on May 12, 2026 at 3:04 pm

    My guess is that you are missing that backslash (‘\’) characters are escape characters in Java String literals. So when you want to use a ‘\’ escape in a regex written as a Java String you need to escape it; e.g.

    Pattern.compile("\.");   // Java syntax error
    
    // A regex that matches a (any) character
    Pattern.compile(".");  
    
    // A regex that matches a literal '.' character
    Pattern.compile("\\.");  
    
    // A regex that matches a literal '\' followed by one character
    Pattern.compile("\\\\.");
    

    The String.split(String separatorRegex) method splits a String into substrings separated by substrings matching the regex. So str.split("\\.") will split str into substrings separated by a single literal ‘.’ character.

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