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Home/ Questions/Q 718899
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T05:34:49+00:00 2026-05-14T05:34:49+00:00

From what I understand: when you pass by value, the function makes a local

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From what I understand: when you pass by value, the function makes a local copy of the passed argument and uses that; when the function ends, it goes out of scope. When you pass by const reference, the function uses a reference to the passed argument that can’t be modified. I don’t understand, however, why one would choose one over the other, except in a situation where an argument needs to be modified and returned. If you had a void function where nothing is getting returned, why choose one over the other?

EDIT: So basically passing by const reference avoids copying the object. So in what situations is copying the object good? I mean, why not just use const references all the time if it optimizes performance all the time?

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  1. Editorial Team
    Editorial Team
    2026-05-14T05:34:50+00:00Added an answer on May 14, 2026 at 5:34 am

    There are two main considerations. One is the expense of copying the passed object and the second is the assumptions that the compiler can make when the object is a a local object.

    E.g. In the first form, in the body of f it cannot be assumed that a and b don’t reference the same object; so the value of a must be re-read after any write to b, just in case. In the second form, a cannot be changed via a write to b, as it is local to the function, so these re-reads are unnecessary.

    void f(const Obj& a, Obj& b)
    {
        // a and b could reference the same object
    }
    
    void f(Obj a, Obj& b)
    {
        // a is local, b cannot be a reference to a
    }
    

    E.g.: In the first example, the compiler may be able to assume that the value of a local object doesn’t change when an unrelated call is made. Without information about h, the compiler may not know whether an object that that function has a reference to (via a reference parameter) isn’t changed by h. For example, that object might be part of a global state which is modified by h.

    void g(const Obj& a)
    {
        // ...
        h(); // the value of a might change
        // ...
    }
    
    void g(Obj a)
    {
        // ...
        h(); // the value of a is unlikely to change
        // ...
    }
    

    Unfortunately, this example isn’t cast iron. It is possible to write a class that, say, adds a pointer to itself to a global state object in its constructor, so that even a local object of class type might be altered by a global function call. Despite this, there are still potentially more opportunities for valid optimizations for local objects as they can’t be aliased directly by references passed in, or other pre-existing objects.

    Passing a parameter by const reference should be chosen where the semantics of references are actually required, or as a performance improvement only if the cost of potential aliasing would be outweighed by the expense of copying the parameter.

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