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Home/ Questions/Q 3458242
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T09:57:31+00:00 2026-05-18T09:57:31+00:00

From what I’ve read the general solution to this is as follows: var DataRequest

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From what I’ve read the general solution to this is as follows:

var DataRequest = $.ajax({ /* ... */ });

and then DataRequest.abort() in the beforeSend ajax event. However, this results in NO requests being sent.

What I’m trying to achieve is to abort any ajax operations that are declared as DataRequest (for example), and allow only the latest request to proceed. Currently I have a button that when clicked starts a request and adds a loading spinner. If I click it many times, I just get a bunch of loading spinners filling up my page. How can I prevent this?

Here’s the relevant code:

beforeSend: function() {
    $('<div class="grid"></div>')
        .attr('id', 'loading')
        .hide()
        .insertBefore('#output')
        .fadeIn();
},

success: function(data) {
    $('#loading').hide(function () {
        $(this).remove();
    });
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T09:57:32+00:00Added an answer on May 18, 2026 at 9:57 am

    Here’s the pattern I use when I need to have multiple requests and only process the last:

    var fooXHR, fooCounter=0;
    $(...).bind( 'someEvent', function(){
      // Do the Right Thing to indicate that we don't care about the request anymore
      if (fooXHR) fooXHR.abort();
    
      var token = ++fooCounter;
      fooXHR = $.get( ..., function(data){
        // Even aborted XHR may cause the callback to be invoked
        if (token != fooCounter) return;
    
        // At this point we know that we're using the data from the latest request
      });
    });
    

    Edit: I have wrapped this functionality up in a plugin-like method call here:
    Cancel a jQuery AJAX call before it returns?

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