Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 9005619
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 16, 20262026-06-16T01:11:39+00:00 2026-06-16T01:11:39+00:00

function A(a, b) { return a[b] * b; } function B(a) { var x

  • 0
  function A(a, b) {
     return a[b] * b;
   }
  function B(a) {

     var x = 0;
     for (var i=5; i>0; i--)
     x += A(a, i);

     return x;
  }
      var aValues = [3,5,9,8,7,1];
      var y = B(aValues);

Would the answer be:
B(1)
B(3)
B(5)
B(7)
B(8)
B(9)
?
Im lost be any push in the right direction would be appreciated.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-16T01:11:40+00:00Added an answer on June 16, 2026 at 1:11 am

    After the execution y is 80.
    The complete array is passed to B(). The loop in B() iterates over the last 5 elements of aValues. Arrays in Javascript start at index 0, so the loop i=5; i>0; i-- never touches the array element with index 0

    Function a() then multiplies the current item with the current index and returns the result (which is added to x)

    So for every loop index you get:

    i=5 -> x += 1 * 5
    i=4 -> x += 7 * 4
    i=3 -> x += 8 * 3
    i=2 -> x += 9 * 2
    i=1 -> x += 5 * 1
    

    So after the loop x contains the value 80 which is returned and assigned to y

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

var a = function () { return 'test'; }(); console.log(a); Answer in First Case
For example: (function() { var proxied = window.eval; window.eval = function() { return proxied.apply(this,
This is my object : var obj = { a:{ x:1 y:function(){return this.x //works
var x= 1; Number.prototype.test = function () { return this }; x.test() === x.test()
var foo = { x: 1, y: (function () { return ++this.x; })() };
Having an object like this: var a = { b: string, c: function(){ return
I find myself doing this repeatedy. $jq(button).filter(function(){ return this.id.match(/^user_(\d+)_edit$/); }).click(function(){ var matches = this.id.match(/^user_(\d+)_edit$/);
var Dog = function() { var _instance = 'hello world'; return function() { console.log(this._instance);
This seems like a straightforward implementation: ko.observableArray.fn.findEl = function(id) { return ko.computed(function() { var
numbers = [1,2,3,4,5,4,3,2,1]; var filterResult = numbers.filter(function(i){ return (i > 2); }); I don't

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.