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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T13:11:55+00:00 2026-05-13T13:11:55+00:00

function ajaxCall(query){ $.ajax({ method:get, url:/main/, data:q=+query, beforeSend:function() {}, success:function(html){ $(#main).html(html); } }); }; This

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function ajaxCall(query){
$.ajax({
    method:"get",
    url:"/main/",
    data:"q="+query,
    beforeSend:function() {},
    success:function(html){
        $("#main").html(html);
    }
    });
};

This is the entire code that will populate #main:

<p>{{ num_results }}, you just searched for {{ query }}</p>

Suppose I have another div called $(“secondary”) ….how would I populate that with {{ num_results }}, which is a part of the code, instead of all of it?

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  1. Editorial Team
    Editorial Team
    2026-05-13T13:11:56+00:00Added an answer on May 13, 2026 at 1:11 pm

    One option is to return json with the data you need for each area.

    $.ajax({
        method:"get",
        url:"/main/",
        dataType: "json",
        data:"q="+query,
        beforeSend:function() {},
        success:function(json){
            $("#main").html(json.main);
            $("#secondary").html(json.secondary);
        }
    });
    

    What you would be returning is:

    {
        "main": "<p>{{ num_results }}, you just searched for {{ query }}</p>",
        "secondary": "{{ num_results }}"
    }
    
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