Question

Function call:

 $trdata .= $this->table_td($tddata, 1, $td);

Function:

public function table_td($data = '', $parameters = array()){
    return($this->table_thtd($data, 0, $parameters));
}

A print_r before the return shows a 1, instead of the data array I’m passing. Any thoughts on what’s going on?

Answer 1

You’re passing a 1 as the second argument to the function call, and your $parameters argument is the second argument in the function definition… what do you expect?