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Home/ Questions/Q 8485427
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T20:38:34+00:00 2026-06-10T20:38:34+00:00

function changeBackground() { var myVar = 100; $(‘div.seventh’).css({background-position: myVar}); } This is my code

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function changeBackground() {
    var myVar = 100;
    $('div.seventh').css({"background-position": myVar});
}

This is my code to make the background image move. It works but only only once… The solution I’ve tried to use to make it work more than once is this:

function changeBackground() {
    var myVar = ($('div.seventh').css('backgroundPositionX'))+100;
    $('div.seventh').css({"background-position": myVar});
}

Problem is that this doesn’t seem to work like I want it to work. I get the right number that I want when doing:

alert($('div.seventh').css('backgroundPositionX'));

But it just won’t work…

Any ideas?…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T20:38:36+00:00Added an answer on June 10, 2026 at 8:38 pm

    You can use the animate() function:

    $('div.seventh').animate({
        'background-position' : '+=50px'
    });
    
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