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Home/ Questions/Q 742651
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:46:20+00:00 2026-05-14T08:46:20+00:00

function convertDT($TS) { $TS = strtotime($TS); $TS -= date(Z); $newTS = date(Y-m-d\TH:i:s\Z, $TS); return

  • 0
function convertDT($TS) {
    $TS = strtotime($TS);
    $TS -= date("Z");
    $newTS = date("Y-m-d\TH:i:s\Z", $TS);
    return $newTS;
}

echo "Good: ".convertDT('2010-04-20 01:23:45')."\n";
echo "Bad: ".convertDT('2010-31-20 01:23:45')."\n";

The second date returns: 1969-12-31T23:00:00Z

Why? Should this error?

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:46:21+00:00Added an answer on May 14, 2026 at 8:46 am

    strtotime() returns false when you give it an invalid timestamp. false is equivalent to 0 if you use it in an integer context, so when you pass it to this line:

    $newTS = date("Y-m-d\TH:i:s\Z", $TS);
    

    You are effectively creating a date from a timestamp of 0. In terms of the UNIX epoch, 0 is January 1st, 1970, which is where you’re getting your end result from.

    Your best bet would be soemthing like this:

    $TS = strtotime($TS);
    if($TS === false) {
        throw new Exception("Invalid timestamp.");
    }
    //etc.
    
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