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Home/ Questions/Q 6687727
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:19:21+00:00 2026-05-26T05:19:21+00:00

function csv_data_to_zip_array($csv) { $f = fopen($csv, r); $i= 0; while($line= fgets($f)){ $line = preg_replace(/[^0-9]/,

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function csv_data_to_zip_array($csv)
{
    $f = fopen($csv, "r");
    $i= 0;
    while($line= fgets($f)){
        $line = preg_replace("/[^0-9]/", "", $line);
        if(is_numeric($line)&&strlen($line)==5){ // it is a zip code
            $array[] = $line;
        }
        $i++;
    }
    fclose($f);
    return $array;
}

That is my function, it’s reading a large csv with a bunch of zip codes into an array.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:19:22+00:00Added an answer on May 26, 2026 at 5:19 am

    It’s what Ignacio said: either the while or if is always returning false, and you should initialize $array as an empty array before that while loop anyway.

    Here is a suggestion for maybe getting results faster: If the CSV always contains the ZIP codes in the same column, use fgetcsv instead. You can then just specify the column number to check (is_numeric(substr($line[column_num],0,5))) rather than running a preg_replace on the whole line.

    Edit:

    Using the sample data you posted from your website (I noticed all data files in there have the zipcode in the first column; some files have a header row and some do not), this function does the trick:

    function csv_data_to_zip_array($csv_path) {
      $fd = fopen($csv_path,'r');
      $zipcodes = array();
      while ($columns = fgetcsv($fd)) {
        if(is_numeric($columns[0])) {
          $zipcodes[] = $columns[0];
        }
      }
      return $zipcodes;
    }
    
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