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Home/ Questions/Q 7002761
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T20:58:13+00:00 2026-05-27T20:58:13+00:00

function extend(o, p) { for(prop in p) { o[prop] = p[prop]; } return o;

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function extend(o, p) {
    for(prop in p) {                        
        o[prop] = p[prop];                  
    }
    return o;
}
function o() {};
function p(){};
p.name='caicai';
p.show=function(){ alert(this.name);};
p.show(); // output p
extend(o, p);
o.show(); // output o

why the “output” in here? why not to output ‘caicai’.

function extend(o, p) {
    for(prop in p) {                        
        o[prop] = p[prop];                  
    }
    return o;
}
function o() {};
function p(){};
p.poo='caicai';
p.show=function(){ alert(this.poo);};
p.show(); // output 'caicai'
extend(o, p);
o.show(); // output 'caicai'

BUT in here ?
why the “output” in here? why not to output ‘caicai’.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T20:58:14+00:00Added an answer on May 27, 2026 at 8:58 pm

    First: This is not related to the extend function.

    o and p are functions. Function.name [MDN] is a non-standard property and cannot be overridden.

    Example:

    > function foo() {}
      undefined
    > foo.name
      "foo"
    > foo.name = 'bar';  // assigning a new value
      "bar"
    > foo.name           // does not work
      "foo"
    

    If you’d declare o and p as objects, then it would work:

    > var foo = {};
      undefined
    > foo.name
      undefined
    > foo.name = 'bar';
      "bar"
    > foo.name
      "bar"
    
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