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Home/ Questions/Q 9167515
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T15:24:34+00:00 2026-06-17T15:24:34+00:00

function nextSong() { var v30 = 1; var v07 = 1; var v……[continues] var

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function nextSong() {
    var v30 = 1;
    var v07 = 1;
    var v......[continues]
    var audioPlayer = document.getElementsByTagName('audio')[0];
    if (v07 == '1') {
        audioPlayer.src='wavs/1507.mp3';
        audioPlayer.load();
        audioPlayer.play();
    }
    if (v30 == '1') {
        audioPlayer.src='wavs/1530.mp3';
        audioPlayer.load();
        audioPlayer.play();            
    }
    if (......[continues]
}

This current configuration plays and loops the ‘1530.mp3’, shouldn’t it also play and loop ‘1507.mp3’ too? Im open to any new method of doing this, like an array, which i think would be a better option. Just not so sure how to do so.

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  1. Editorial Team
    Editorial Team
    2026-06-17T15:24:36+00:00Added an answer on June 17, 2026 at 3:24 pm
    audioPlayer.src='wavs/1507.mp3';
    audioPlayer.src='wavs/1530.mp3';
    

    You are setting the source twice on the same element, which results in it only playing the second source (1530.mp3) as it overwrites the first source (1507.mp3).

    You need two audio elements to play two files.

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