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Home/ Questions/Q 7511563
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T23:35:21+00:00 2026-05-29T23:35:21+00:00

function readMemory(ptr, size) { $.post(readMemory.php, { ptr : ptr, size : size}, function(data) {

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function readMemory(ptr, size)
{
    $.post("readMemory.php", { ptr : ptr, size : size}, function(data)
    {

    });     

    //return "data"
}

Hi, I just want to get data variable as return of readMemory function. Is there any proper way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-29T23:35:23+00:00Added an answer on May 29, 2026 at 11:35 pm

    The best thing to do is use a callback:

    function readMemory(ptr, size, callback)
    {
        $.post("readMemory.php", { ptr : ptr, size : size}, function(data)
        {
            callback(data, ptr, size);
        });     
    }
    

    (Note that we have ptr and size being passed to callback as well as data; this is usually good practice.)

    So code you were expecting to use readMemory like this:

    var data = readMemory(ptr, 100);
    doSomethingWith(data);
    doSomethingElseWith(data);
    

    …will instead look like this:

    readMemory(ptr, 100, function(data) {
        doSomethingWith(data);
        doSomethingElseWith(data);
    });
    

    This is because your readMemory function only starts the POST operation; it returns before the operation completes (the operation is asynchronous).

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