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Home/ Questions/Q 7814207
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T05:07:43+00:00 2026-06-02T05:07:43+00:00

function showimage($zip_file, $file_name) { if (file_exists($zip_file)) { $zip = zip_open($zip_file); while ($zip_entry = zip_read($zip))

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function showimage($zip_file, $file_name) {
    if (file_exists($zip_file)) {
        $zip = zip_open($zip_file);
        while ($zip_entry = zip_read($zip)) {
            if (zip_entry_open($zip, $zip_entry, "r")) {
                if (zip_entry_name($zip_entry) == $file_name) {
                    $theimg = zip_entry_read($zip_entry, zip_entry_filesize($zip_entry));
                    $theimg = imagecreatefromstring($theimg);
                    if ($theimg !== false) {
                        header('Content-Type: image/jpeg');
                        imagejpeg($theimg);
                        imagedestroy($theimg);
                    }
                    else { echo "Could not create image."; }
                    zip_entry_close($zip_entry);
                }
            }
            else { echo "Could not open."; }
        }
        zip_close($zip);
    }
    else { echo "File not found."; }
}

I’m running this function to open a specified zip file and then looping through the contents to find the specified file name, then creating an image from that file without the need to extract. I was just kind of curious how system intensive this process was, and if there was a neater/more direct manner of finding a file within a zip archive without the need to loop through and see if the name matches the given file name. Is there anyway to call a file directly from the zip file with the given name, assuming it exists?

The above code works… I guess I’m just trying to see how to do it better. If that makes sense.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-02T05:07:45+00:00Added an answer on June 2, 2026 at 5:07 am

    ZipArchive has a method for getting the file without actually searching for it.

    function showimage($zip_file, $file_name) {
        $z = new ZipArchive();
        if ($z->open($zip_file) !== true) {
            echo "File not found.";
            return false;
        }
    
        $stat = $z->statName($file_name);
        $fp   = $z->getStream($file_name);
        if(!$fp) {
            echo "Could not load image.";
            return false;
        }
    
        header('Content-Type: image/jpeg');
        header('Content-Length: ' . $stat['size']);
        fpassthru($fp);
        return true;
    }
    
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