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Home/ Questions/Q 6716877
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T08:47:09+00:00 2026-05-26T08:47:09+00:00

function slide() { if($(‘.current’).is(‘:last-child’)){ $(‘.current’).removeClass(‘.current’); $(‘#imgholder’).first().addClass(‘.current’); $(‘#imgholder’).animate({left: ‘3920px’}); } else{ $nxt=$(.current); $(.current).removeClass(current); $nxt.next().addClass(current); $(‘#imgholder’).animate({left:

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function slide()
{
    if($('.current').is(':last-child')){
        $('.current').removeClass('.current');
        $('#imgholder').first().addClass('.current');
        $('#imgholder').animate({left: '3920px'});
    }
    else{
        $nxt=$(".current");
        $(".current").removeClass("current");
        $nxt.next().addClass("current");
        $('#imgholder').animate({left: '-=980'},{duration: 'slow', easing: 'easeOutBounce' });
        }
}
var loop_handle= setTimeout("slide()",'3000');

I have put this code in header section and the setTimeout runs only once.

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  1. Editorial Team
    Editorial Team
    2026-05-26T08:47:09+00:00Added an answer on May 26, 2026 at 8:47 am

    setTimeout should only run once. You’re looking for setInterval.

    var loop_handle = setInterval(slide, 3000);
    

    Also, the second argument should be a number, not a string. When the function call doesn’t require any arguments, it’s better to reference to the function instead of using a string. A string would be converted to a function. This function will be executed within the scope of the window.

      setInterval("slide()", 3000);
    //becomes
      setInterval(Function("slide();"), 3000);
    
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