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Home/ Questions/Q 4623140
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:56:37+00:00 2026-05-22T02:56:37+00:00

$(function () { var mainimagepanel = $(#blah1); var postimagepanel = $(#blah2); }); both object

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$(function () {
            var mainimagepanel = $("#blah1");
            var postimagepanel = $("#blah2");
   });

both object exist on the page where i run my $. can someone show me why i got exception mainimagepanel is not defined

the exception caused in Firebug or Chrome dev tool. so someone can tell me reason and how i can check that a input control exist on both.

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:56:38+00:00Added an answer on May 22, 2026 at 2:56 am

    Your variables are declared inside the anonymous function, and that is their scope. They do not exist outside that function. To fix it, you can do something like:

    var mainimagepanel, postimagepanel;
    
    $(function () {
      mainimagepanel = $("#blah1");
      postimagepanel = $("#blah2");
    });
    

    It is however usually good advice to limit your variables so that they exist in the tightest possible scope.

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