Question

        $(function() {  
            var number = document.getElementById("breuken");        

            var i=0;

                for (i=1;i<=10;i++){
                    var fRandom = Math.floor(Math.random()*10);
                    var sRandom = Math.floor(Math.random()*10);

                    var calc = fRandom - sRandom;

                    number.innerHTML += "" + fRandom + " - " + sRandom + " = " + calc + "<br />";
                }       

            number.innerHTML;
        });

Basically, what it does now is it shows 2 random numbers under 10. it subtracts the second number from the first number.

What I would like is to have the first number always be higher than the second number so I won’t get any answers like ‘-3’.

Answer 1

just use Math.abs() ?

var calc = Math.abs(fRandom - sRandom);

In case orders are important, you can also do

                var sRandom = Math.floor(Math.random()*10);

                // lower bound of sRandom, upper bound of (10 - sRandom)
                var fRandom = Math.floor(sRandom + Math.random()*(10-sRandom));