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Home/ Questions/Q 970521
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T02:49:07+00:00 2026-05-16T02:49:07+00:00

gcc 4.4.4 c89 I have the following structure. struct device_sys { char device[STRING_SIZE]; int

  • 0

gcc 4.4.4 c89

I have the following structure.

struct device_sys
{
    char device[STRING_SIZE];
    int id;
    char category;
};

int main(void)
{
    struct device_sys dev_sys[NUM_DEVICES];

    memset(dev_sys, 0, (size_t)NUM_DEVICES * sizeof(dev_sys));

    return 0; 
}

I get a stack dump when I call memset. Is this not the correct way to initialize an structure array?

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  1. Editorial Team
    Editorial Team
    2026-05-16T02:49:08+00:00Added an answer on May 16, 2026 at 2:49 am

    Either

    memset(&dev_sys, 0, sizeof dev_sys);
    

    or

    memset(dev_sys, 0, NUM_DEVICES * sizeof(struct device_sys));
    

    Or, if you prefer

    memset(dev_sys, 0, NUM_DEVICES * sizeof *dev_sys);
    

    but not what you have in your original variant.

    Note, that in your specific case in all variants you can use either &dev_sys or dev_sys as the first argument. The effect will be the same. However, &dev_sys is more appropriate in the first variant, since if follows the memset(ptr-to-object, object-size) idiom. In the second and third variants it is more appropriate to use dev_sys (or &dev_sys[0]), since it follows the memset(ptr-to-first-element, number-of-elements * element-size) idiom.

    P.S. Of course, instead of using all that hackish memset trickery, in your particular case you should have just declared your array with an initializer

    struct device_sys dev_sys[NUM_DEVICES] = { 0 };
    

    No memset necessary.

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