Home/ Questions/Q 6054403
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-23T08:08:56+00:00

Getting my self a bit confused here. I would like to test if a

  • 0

Getting my self a bit confused here.

I would like to test if a set of bits (3 bits) contains a bit in a certain postion. 

if (B110 & B010 == B010)

(B110 being the number to check, B010 the bit I want to see if is there)

The above code isn’t giving me the expected out come, both B110 is true and B101 is true. I am pretty sure that I need to use a &(and) to test with the mask B010.

My understanding is that B110 & B010 would be equal to B010 and that B101 & B010 would equal B000. But my if statement is run with both test bits?

I am coding in an Arduino, I’m sure that it’s a simple misunderstanding on my behalf but not sure where.

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Try if ((B110 & B010) == B010)

    At the moment it’s running as if (B110 & (B010 == B010)) which will always be true.

    As this table shows, == and != have a higher precedence than &, | etc.

    • 0