Question

Getting started with Django 1.3 here. Loving the system so far, but struggling on stuff. Also loving stackoverflow for the Q&As. 🙂

I’m currently working on getting logins & registrations working and I’m getting a TemplateSyntaxError with my login view.

Template error

In template /templates/login.html, error at line 9
Caught SyntaxError while rendering: (‘invalid syntax’, (‘/userProfile/views.py’, 47, 52, “\t\treturn render_to_response(‘login.html’, {‘form’: })\n”))

I’ve copy-pasted the code from Django’s auth documentation for a login view:

{% extends "base.html" %}
{% load url from future %}

{% block body-content %}

{% if form.errors %}
<p>Your username and password didn't match. Please try again.</p>
{% endif %}

<form method="post" action="{% url django.contrib.auth.views.login %}">
{% csrf_token %}
<table>
<tr>
    <td>{{ form.username.label_tag }}</td>
    <td>{{ form.username }}</td>
</tr>
<tr>
    <td>{{ form.password.label_tag }}</td>
    <td>{{ form.password }}</td>
</tr>
</table>

<input type="submit" value="login" />
<input type="hidden" name="next" value="{{ next }}" />
</form>

{% endblock %}

Django is breaking on the following line –

<form method="post" action="{% url 'django.contrib.auth.views.login' %}">

I’ve tried removing the single quotes, adding quotes, removing the future url loading but nothing seems to be working. I’ve read the NoReverseMatch question but it doesn’t seem to apply.

Answer 1

The problem is not in your template but rather in your views.py file, line 47:

return render_to_response('login.html', {'form': })

The render_to_response function expects a template name (here: login.html) and a dictionary (here: {'form': }). However, your dictionary contains a syntax error: You have provided a key (form) but are missing a value.

The correct syntax should be something like:

return return render_to_response('login.html', {'form': my_form})