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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T11:50:20+00:00 2026-06-06T11:50:20+00:00

Given a amazon product URL, which can either be http://amazon.com/gp/product/ASIN/* http://amazon.com/*/dp/ASIN/* http://amazon.com/dp/ASIN/* how do

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Given a amazon product URL, which can either be

http://amazon.com/gp/product/ASIN/*
http://amazon.com/*/dp/ASIN/*
http://amazon.com/dp/ASIN/*

how do i scrap the ASIN number from the URL in Ruby ? I am not good at writing regular expressions.

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  1. Editorial Team
    Editorial Team
    2026-06-06T11:50:23+00:00Added an answer on June 6, 2026 at 11:50 am

    Use should find match by:

    scan(/https?:\/\/(?:www\.|)amazon\.com\/(?:gp\/product|[^\/]+\/dp|dp)\/([^\/]+)/)
    
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