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Home/ Questions/Q 4098798
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T20:20:58+00:00 2026-05-20T20:20:58+00:00

Given a consistently seeded Random: Random r = new Random(0); Calling r.Next() consistently produces

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Given a consistently seeded Random:

Random r = new Random(0);

Calling r.Next() consistently produces the same series; so is there a way to quickly discover the N-th value in that series, without calling r.Next() N times?

My scenario is a huge array of values created via r.Next(). The app occasionally reads a value from the array at arbitrary indexes. I’d like to optimize memory usage by eliminating the array and instead, generating the values on demand. But brute-forcing r.Next() 5 million times to simulate the 5 millionth index of the array is more expensive than storing the array. Is it possible to short-cut your way to the Nth .Next() value, without / with less looping?

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  1. Editorial Team
    Editorial Team
    2026-05-20T20:20:58+00:00Added an answer on May 20, 2026 at 8:20 pm

    In theory if you knew the exact algorithm and the initial state you’d be able to duplicate the series but the end result would just be identical to calling r.next().

    Depending on how ‘good’ you need your random numbers to be you might consider creating your own PRNG based on a Linear congruential generator which is relatively easy/fast to generate numbers for. If you can live with a “bad” PRNG there are likely other algorithms that may be better to use for your purpose. Whether this would be faster/better than just storing a large array of numbers from r.next() is another question.

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