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Given a date I can access the appropriate element in a zoo vector.
For example:
z[as.POSIXct(1213708500, origin="1970-01-01")]
this returns
2008-06-17 14:15:00
-8.28123
I would like to get a vector of 30 consecutive elements (ending with the element above).
How do I do that (efficiently) without knowing the time stamp of the starting element?
I know that I can do this with the window function, but it requires a start time and an end time.
Use something like
followed by
where the
which()gives you the index of the match, from which you can then pick the thirty consecutive elements by normal indexing.