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Home/ Questions/Q 8195601
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T05:11:30+00:00 2026-06-07T05:11:30+00:00

Given a list (a) and a numeric vector (b) of the same length as

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Given a list (a) and a numeric vector (b) of the same length as a:

a <- list(1, c(3, 7), 5)
b <- c(1,1,2)

How to create a new list of length max(b) where every element in a is put in the corresponding index according to b and combined if multiple occurrences occur, so that you get:

[[1]]
[1] 1 3 7

[[2]]
[1] 5

This should hopefully be done very efficiently (no loops), as the dimensions of my data tends to be very big…

I’m quite sure there is an obvious solution I haven’t thought about…

Thanks for the help

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  1. Editorial Team
    Editorial Team
    2026-06-07T05:11:31+00:00Added an answer on June 7, 2026 at 5:11 am

    What about:

    split(unlist(a), rep(b, sapply(a, length)))
    $`1`
    [1] 1 3 7
    
    $`2`
    [1] 5
    
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