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Home/ Questions/Q 8495765
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T23:39:51+00:00 2026-06-10T23:39:51+00:00

Given a list of lists: >>> n=4 >>> LoL=[range(n) for i in range(n)] >>>

  • 0

Given a list of lists:

>>> n=4
>>> LoL=[range(n) for i in range(n)]
>>> LoL
[[0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3], [0, 1, 2, 3]]

Is it readily apparent, understandable, Pythonic even to assure a N x N matrix this way:

>>> len(LoL) == n and {len(l) for l in LoL} == {n}
True

So it would be used thus:

if len(matrix) != 4 or {len(l) for l in matrix} != {4}:
        raise ValueError

Is there a better alternative idiom or is this understandable?

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  1. Editorial Team
    Editorial Team
    2026-06-10T23:39:53+00:00Added an answer on June 10, 2026 at 11:39 pm

    As stated in your comment, try / except is probably better.

    Not only will you catch and attempt to use an element outside of the 4×4 size, but you will also catch the wrong dimensions passed to you:

    >>> LoL=[1,2,3,4]
    >>> len(LoL) == n and {len(l) for l in LoL} == {n}
    Traceback (most recent call last):
    File "<stdin>", line 1, in <module>
    File "<stdin>", line 1, in <setcomp>
    TypeError: object of type 'int' has no len()
    

    Vs, if you have doubt about the data you are about to use:

    >>> try: 
    ...    i=LoL[2][2]
    ... except IndexError:
    ...    print 'no bueno...'
    ... 
    no bueno...
    
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