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Editorial Team
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Asked: 2026-05-13T09:14:34+00:00

Given a local directory structure of /foo/bar , and assuming that a given path

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Given a local directory structure of /foo/bar, and assuming that a given path contains exactly one file (filename and content does not matter), what is a reasonably fast way to get the filename of that single file (NOT the file content)?

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1 Answer

  1. Editorial Team

    1st element of os.listdir()

    import os
os.listdir('/foo/bar')[0]
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