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Editorial Team
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Asked: 2026-06-10T13:05:04+00:00

Given a Neo4J Node with an array property, how do I create a Cypher

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Given a Neo4J Node with an array property, how do I create a Cypher query to return only the node(s) that match an array literal?

Using the console I created a node with the array property called “list”:

neo4j-sh (0)$ create n = {list: [1,2,3]};
==> +-------------------+
==> | No data returned. |
==> +-------------------+
==> Nodes created: 1
==> Properties set: 1
==> 83 ms

neo4j-sh (0)$ start n=node(1) return n;
==> +-----------------------+
==> | n                     |
==> +-----------------------+
==> | Node[1]{list:[1,2,3]} |
==> +-----------------------+
==> 1 row
==> 1 ms

However, my query does not return the Node that was just created given a WHERE clause that matches an array literal:

neo4j-sh (0)$ start n=node(1) where n.list=[1,2,3] return n;
==> +---+
==> | n |
==> +---+
==> +---+
==> 0 row
==> 0 ms

It’s entirely possible I’m mis-using Cypher. Any tips on doing exact array property matching in Cypher would be helpful.

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1 Answer

  1. Editorial Team

    The console is always running the latest SNAPSHOT builds of Neoj4. the version refers to the Cypher Syntax parswer, we will point that out more clearly 🙂

    Now, there has been some fixing around the Array handling in Cypher, see https://github.com/neo4j/community/pull/815 and https://github.com/neo4j/community/issues/818 which problably are the ones that make the console work. This has been merged in after 1.8.M07, so in order to get it work locally, please download one of the latest 1.8.-SNAPSHOT, build it from GITHUB or wait for 1.8.M08 which is due very soon.

    /peter

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