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Home/ Questions/Q 8900591
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T01:08:04+00:00 2026-06-15T01:08:04+00:00

Given a pair of lat/lng values, how do I determine if the pair is

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Given a pair of lat/lng values, how do I determine if the pair is within a polygon? I need to do this in PHP. I see that Google Maps API has a containsLocation method: https://developers.google.com/maps/documentation/javascript/reference. Is there a way to leverage this from PHP?

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  1. Editorial Team
    Editorial Team
    2026-06-15T01:08:05+00:00Added an answer on June 15, 2026 at 1:08 am

    One way to find if a point is in a polygon is to count how many times a line drawn from the point (in any direction) intersects with the polygon boundary. If they intersect an even number of times, then the point is outside.

    I have implemented the C code from this Point in Polygon article in php and used the polygon below to illustrate.

    polygon

    <?php
    //Point-In-Polygon Algorithm
    $polySides  = 4; //how many corners the polygon has
    $polyX    =  array(4,9,11,2);//horizontal coordinates of corners
    $polyY    =  array(10,7,2,2);//vertical coordinates of corners
    $x = 3.5;
    $y = 13.5;//Outside
    //$y = 3.5;//Inside
    
    function pointInPolygon($polySides,$polyX,$polyY,$x,$y) {
      $j = $polySides-1 ;
      $oddNodes = 0;
      for ($i=0; $i<$polySides; $i++) {
        if ($polyY[$i]<$y && $polyY[$j]>=$y 
     ||  $polyY[$j]<$y && $polyY[$i]>=$y) {
        if ($polyX[$i]+($y-$polyY[$i])/($polyY[$j]-$polyY[$i])*($polyX[$j]-$polyX[$i])<$x)    {
        $oddNodes=!$oddNodes; }}
       $j=$i; }
    
      return $oddNodes; }
    
    
     if (pointInPolygon($polySides,$polyX,$polyY,$x,$y)){
      echo "Is in polygon!";
    }
    else echo "Is not in polygon";
    ?>
    
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