Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 564039
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T12:43:27+00:00 2026-05-13T12:43:27+00:00

Given a representation of database tables where two entities are connected through a join

  • 0

Given a representation of database tables where two entities are connected through a join table, is it possible to sort on the other entity specifying the sort order somehow through annotations?

Consider, roughly, the following database tables:

actor ( id, name )
credit ( actorId, movieId, roleName )
movie ( id, title, year )

And hibernate entities like:

@Entity
class Actor {
    @Id
    Integer id;
    @Column
    String name;
    @OneToMany
    @JoinColumn(name = "actorId")
    List<Credit> credits;
}

@Entity
class Credit {
    @Column
    String roleName;
    @ManyToOne
    @JoinColumn(name = "movieId")
    Movie movie;
}

@Entity
class Movie {
    @Id
    Integer id;
    @Column
    Integer year;
    @Column
    String title;
}

So I’d like to be able to have the default sorting order return Credits for an Actor in descending order by the year of the movie:

actor.getCredits(); // Returns credits in order of Credit.movie.year

It seems like one level deep of joining is pretty straightforward to sort by using @OrderBy, for example @OrderBy(“roleName”) … but how do I go another join deeper?

Thanks!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T12:43:27+00:00Added an answer on May 13, 2026 at 12:43 pm

    According to JPA specification:

    The property or field name must correspond to that of a persistent property or field of the associated class

    It explains why @OrderBy(“movie.year”) does not work as expected

    Unless you use a HQL query, you should use encapsulation to get your goal

    @Entity
    public class Actor {
    
        private List<Credits> credits = new ArrayList<Credits>();
    
        @OneToMany
        @JoinColumn(name="ACTOR_ID")
        public List<Credits> getCredits() {
            return this.credits;
        }
    
        @Transient
        public List<Credits> getCreditsOrderedByMovieYear() {
            Collections.sort(credits, new Comparator<Credits>() {
                public int compare(Credits o1, Credits o2) {
                    // Integer implements Comparable<T>
                    return o1.getMovie().getYear().compareTo(o2.getMovie().getYear());
                }
            });
    
            return credits;
        }
    
    }
    

    Sometimes, when Hibernate does not provide some custom behavior, i use encapsulation to get my goal

    regards,

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 357k
  • Answers 357k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer The other answers are correct. Here is some code you… May 14, 2026 at 9:40 am
  • Editorial Team
    Editorial Team added an answer you ruin the noConflict concept by reassigning the jquery to… May 14, 2026 at 9:40 am
  • Editorial Team
    Editorial Team added an answer If you get that particular error, you don't actually have… May 14, 2026 at 9:40 am

Related Questions

No related questions found

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.