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Home/ Questions/Q 7777821
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T18:14:24+00:00 2026-06-01T18:14:24+00:00

Given a Runnable object e.g. public class Test implements Runnable { @Override public void

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Given a Runnable object e.g.

public class Test implements Runnable {

    @Override
    public void run() {

        int x = 2;
        int y = 6;
        // Snip more code
        int w = x - 1;
        int z = x * y;          

    }

}

I’d like to be able to execute an exact number of operations e.g.

Test t = new Test();
Executor.execute(t, 100); // Arbitrary unit of operations

Such that if the first time I do this execution runs up to:

int w = x - 1;

Any other time I call the method with the same parameters will result in execution up to the same point.

I’ve had a look around and can’t see anything suitable (e.g. ScheduledThreadPoolExecutor won’t work as far as I can tell).

Will I have to move to the bytecode level to make this worK? From what I’ve read the JIT may cause problems here too.

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  1. Editorial Team
    Editorial Team
    2026-06-01T18:14:25+00:00Added an answer on June 1, 2026 at 6:14 pm

    You can inject byte code so that it check the timeout after every operation. This could make it 100x slower or more, but it would be deterministic.

    A more pragmatic apporach would be to check the timeout at inveals of your chosing by adding code to the Runnable.

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