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Home/ Questions/Q 6619791
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T21:00:56+00:00 2026-05-25T21:00:56+00:00

Given a template class: template<class T> class Foo { public: void FunctionThatCreatesT() { _object

  • 0

Given a template class:

template<class T>
class Foo
{
public:
    void FunctionThatCreatesT()
    {
        _object = new T;
    }
private:
    shared_ptr<T> _object;
}

Is it possible to somehow pass a set of constructor parameters for T to Foo (perhaps when Foo is constructed) such that Foo can use them when it creates T? A C++11 only solution is fine (so, variadics are on the table for example).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T21:00:57+00:00Added an answer on May 25, 2026 at 9:00 pm

    Exactly that, variadic templates and perfect forwarding via std::forward.

    #include <memory>
    #include <utility>
    
    template<class T>
    class Foo
    {
    public:
        template<class... Args>
        void FunctionThatCreatesT(Args&&... args)
        {
            _object = new T(std::forward<Args>(args)...);
        }
    private:
        std::shared_ptr<T> _object;
    }
    

    For a listing of how this works, see this excellent answer.

    You can emulate a limited version of this in C++03 with many overloaded functions, but.. it’s a PITA.

    Also, this is only from memory, so no testing done. Might contain an off-by-one error.

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