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Home/ Questions/Q 6159769
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T21:11:17+00:00 2026-05-23T21:11:17+00:00

Given a text, how could I count the density / count of word lengths,

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Given a text, how could I count the density / count of word lengths, so that I get an output like this

  • 1 letter words : 52 / 1%
  • 2 letter words : 34 / 0.5%
  • 3 letter words : 67 / 2%

Found this but for python

  • counting the word length in a file
  • Index by word length
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  1. Editorial Team
    Editorial Team
    2026-05-23T21:11:17+00:00Added an answer on May 23, 2026 at 9:11 pm

    You could start by splitting your text into words, using either explode() (as a very/too simple solution) or preg_split() (allows for stuff that’s a bit more powerful) :

    $text = "this is some kind of text with several words";
    $words = explode(' ', $text);
    

    Then, iterate over the words, getting, for each one of those, its length, using [**`strlen()`**][3] ; and putting those lengths into an array :

    $results = array();
    foreach ($words as $word) {
        $length = strlen($word);
        if (isset($results[$length])) {
            $results[$length]++;
        }
        else {
            $results[$length] = 1;
        }
        
    }
    

    If you’re working with UTF-8, see mb_strlen().

    At the end of that loop, `$results` would look like this :

    array
      4 => int 5
      2 => int 2
      7 => int 1
      5 => int 1
    

    The total number of words, which you’ll need to calculate the percentage, can be found either :

    • By incrementing a counter inside the foreach loop,
    • or by calling array_sum() on $results after the loop is done.

    And for the percentages’ calculation, it’s a bit of maths — I won’t be that helpful, about that ^^

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