Question

Given a timestamp in ISO 8601 format below:

2012-04-21T01:56:00.581550

what regular expression would remove the decimal point and the millisecond precision? In other words, a regex that applies to the above and returns the following:

2012-04-21T01:56:00

This is probably very simple, but not being particular familiar with regex I am unsure how to approach the solution. Thanks in advance for any assistance.

Answer 1

If you must use regex, you can use "[.][0-9]+$" and replace it with an empty string "".
It is easier to locate the trailing '.', and chop off the string at its index. In C#, that would be

myStr = myStr.Substring(0, myStr.LastIndexOf('.')-1);