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Home/ Questions/Q 9109935
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T03:09:32+00:00 2026-06-17T03:09:32+00:00

Given a two-dimensional coordinate system how can I find all points with integer coordinates

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Given a two-dimensional coordinate system how can I find all points with integer coordinates in a radius from a given point? I want the points as x-coordinate and y-coordinate value.

Finding points in a square around the given point is easy and could be done like that:

for(int x = -radius + point.x; x < radius + point.x; ++x)
for(int y = -radius + point.y; y < radius + point.y; ++y)
{
    points.insert(point(x, y));
}

But how can I find the points in a circle around the given point? This algorithm is performance related but not accuracy related. So it doesn’t matter if a point closes to the radius than 1 is added or not. In other words, I do not need floating point accuracy.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T03:09:34+00:00Added an answer on June 17, 2026 at 3:09 am

    Simplest solution: take a square and filter it:

    Point point(100, 100);
    for(int x = -radius; x <= radius; ++x)
    for(int y = -radius; y <= radius; ++y)
    if(x*x + y*y <= radius* radius)   {
        points.insert(Point(x + point.x, y + point.y));
    }
    
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