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Home/ Questions/Q 1105487
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:38:27+00:00 2026-05-17T01:38:27+00:00

Given a type such as: public class FooList : List<Foo> { public string SomeMessage

  • 0

Given a type such as:

public class FooList : List<Foo>
{
    public string SomeMessage { get; set; }
}

How can I get the SomeMessage property to be serialized along with the collection without overriding serialization itself?

What I am getting is:

<FooList>
    <Foo />
    <Foo />
    <Foo />
</FooList>

and what I want is:

<FooList>
    <SomeMessage />
    <Foo />
    <Foo />
    <Foo />
</FooList>

For whatever reason, (I think it is because the serialization being used for the generic list doesn’t see the new property) it isn’t being written out.

In case it matters, here is what I am using to serialize it.

FooList content = new FooList();
content.SomeMessage="this is a test";
//add foos

using (TextWriter writer = new StreamWriter("C:\\foos.xml"))
{
    XmlSerializer serializer = new XmlSerializer(typeof(FooList));
    serializer.Serialize(writer, content);
}
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  1. Editorial Team
    Editorial Team
    2026-05-17T01:38:27+00:00Added an answer on May 17, 2026 at 1:38 am

    When the XmlSerializer serializes a collection, it only takes the items of the collection into account. Any extra property declared in the class is ignored. You will either have to implement IXmlSerializable to provide your own serialization logic, or change the design of your class.

    You could do something like that:

    [XmlRoot("FooList")]
    public class FooListContainer
    {
        public string SomeMessage { get; set; }
    
        [XmlElement("Foo")]
        public List<Foo> Foos { get; set; }
    }
    
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